On 16/02/2010 19:44, Aahz wrote:
In article<4b7a91b1.6030...@lonetwin.net>, steve<st...@lonetwin.net>  wrote:
On 02/16/2010 05:49 PM, W. eWatson wrote:

See Subject. a = [1,4,9,3]. Find max, 9, then index to it, 2.

The most obvious would be a.index(max(a)). Is that what you wanted ?

The disadvantage of that is that it's O(2N) instead of O(N).

<Tongue-in-cheek> Well you could do this:

a.sort ()
return -1

TJG
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