John Posner <jjpos...@optimum.net> writes: [...] >> x = s[0] [...] > assigns the name *x* to the object that *s[0]* refers to
s[0] does not refer to an object, it *is* an object (once evaluated of course, otherwise it's just a Python expression). -- Arnaud -- http://mail.python.org/mailman/listinfo/python-list
