dont call the .run() method, call the .start() method which is defined the Thread class (and should NOT be overridden).
tftpserv.start() xmlserv.start() On Fri, Feb 12, 2010 at 10:57 PM, Jordan Apgar <twistedphr...@gmail.com>wrote: > I'm trying to run two servers in the same program at once. Here are > the two: > class TftpServJ(Thread): > def __init__(self, ip, root, port=69, debug = False ): > Thread.__init__(self) > setup stuff here > > def run(self): > try: > self.server.listen(self.ip, self.port) > except KeyboardInterrupt: > pass > > and > class XMLServer(Thread): > def __init__(self, host, port, hostid, rsa_key): > Thread.__init__(self) > setup stuff > > def run(self): > self.server.serve_forever() > > > I call them as: > tftpserv = TftpServJ(host, "/home/twistedphrame/Desktop/xmlrpc_server/ > server") > tftpserv.run() > xmlserv = XMLServer(host, port, HostID, key) > xmlserv.run() > > > it seems that tftpserv runs but wont go on to spawn xmlserv as well. > do I need to fork if I want both these to run at the same time? It > was my impression that by using Thread execution in the main program > would continue. > > > > -- > http://mail.python.org/mailman/listinfo/python-list >
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