I would want to get the output from `logging.exception` but with
traceback from the caller function (I've already all that
information).
This would be the error with logging.exception:
--------------------
ERROR:
PipeError('/bin/ls -l | ', 'no command after of pipe')
Traceback (most recent call last):
File "/data/neo/Proyectos/Python/Scripy/lib/scripy/shell.py", line
160, in __call__
raise PipeError(command, 'no command after of pipe')
PipeError: ('/bin/ls -l | ', 'no command after of pipe')
--------------------
And I've trying it with:
--------------------
message = "File \"{0}\", line {1}, in {2}\n\n {3}".format(
file, line, function, caller)
logging.error(message)
ERROR:
File "/data/neo/Proyectos/Python/Scripy/lib/scripy/shell.py", line
163, in __call__ return self.throw(PipeError, command, 'no
command after of pipe')
--------------------
Could be used `logging.LogRecord` [1] to get it? How?
[1] http://docs.python.org/library/logging.html#logging.LogRecord
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