thinke365 wrote:
jesus, now i fixed it, using odd lambda sort.
l.sort(lambda x,y: cmp(len(x), len(y)))
print l
BUT I AM STILL CONFUSED WHY COSTOMIZED SORT FAILED TO SORT AS IT IS
PROGRAMMER!
thinke365 wrote:
i mean the output i want is:
[ [1, 2], [1, 2, 3, 4], [1, 2, 3, 4, 5]], that is sort according to the
length of the list element
thinke365 wrote:
l = list()
l1 = list((1, 2, 3, 4))
l2 = list((1,2))
l3 = list((1, 2, 3, 4, 5))
l.append(l1)
l.append(l2)
l.append(l3)
print l
def sort_by_list(E1, E2):
print len(E1), len(E2)
return len(list(E1)) > len(list(E2))
l.sort(cmp=sort_by_list)
print l
output:
[[1, 2, 3, 4], [1, 2], [1, 2, 3, 4, 5]]
2 4
5 2
[[1, 2, 3, 4], [1, 2], [1, 2, 3, 4, 5]]
the order of the elements in the list did not change!
When comparing [1, 2] with [1, 2, 3, 4] you want it to return -1 to say
that it's shorter, so they should therefore be swapped, but you're
returning 0 (False), which says it's the same length, so they're not
swapped.
This is also works:
l.sort(lambda x,y: len(x) - len(y))
because the sort really only looks at the sign.
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