Gilles Ganault <nos...@nospam.com> writes:
> On Fri, 22 Jan 2010 09:49:32 -0500, Dave Angel <da...@ieee.org> wrote:
>>Seems to me the other solutions I've seen so far are more complex than
>>needed. I figure you either want an unordered list, in which case you
>>could use random.shuffle(), or you want a list that's sorted, but starts
>>somewhere in the middle, at an arbitrary place, goes to the end, and
>>wraps back to the beginning. So use random.randint() to choose an index
>>within the list, and concatenate two slices of the list, based on that
>>index in reverse order.
>
> Yes, this is exactly what I need: Start listing items from a given
> index (actually, using a character since the list contains names) all
> the way to the end of the list; If the character wasn't the very
> first, go back to the first time and display the list until we get to
> the current character.
>
> Python is so feature-rich, I'm sure there's a much simpler way to do
> this than this crappy code of mine:
>
> =============
> connected = []
> connected.append("0dummy")
> connected.append("aa")
> connected.append("bb")
> connected.append("cc")
>
> index = 0
> for item in connected:
> #For testing purposes;
> #Final code will read/increment character from file
> if item[index] == "b":
> break
> else:
> index = index + 1
>
> #Print items between current character and end of list
> tempindex = index
> while(tempindex < len(connected)):
> print connected[tempindex]
> tempindex = tempindex + 1
>
> #if current letter not first character,
> #display beginning of list up to current character
> if index != 0:
> tempindex = 0
> while tempindex < index:
> print connected[tempindex]
> tempindex = tempindex + 1
> =============
>
> Thank you for any help
Here's a straightforward way to do it, taking advantage of negative
indices (no doubt there are many others):
>>> connected = '0dummy aa bb cc'.split()
>>> connected
['0dummy', 'aa', 'bb', 'cc']
>>> startindex = random.randrange(len(connected))
>>> startindex
2
>>> for i in xrange(startindex - len(connected), startindex):
... print connected[i]
...
bb
cc
0dummy
aa
>>>
connected[-1] is the last element of connected
connected[-2] is the one before last
etc...
I'll let you figure out why the loop works as it does.
HTH
--
Arnaud
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