Wilbert Berendsen <wbs...@xs4all.nl> wrote: > # sort the keys, longest first, so 'aa' gets matched before 'a', because > # in Python regexps the first match (going from left to right) in a > # |-separated group is taken > keys = sorted(mapping.keys(), key=len, reverse=True) >
This would do just as well (although see Iain King's response for the correct answer): keys = sorted(mapping, reverse=True) You don't need to specify key=len because the default sorting for two strings where one is a prefix of the other will always sort them that way anyway, and you don't need to call mapping.keys() because that's what sorted will sort anyway. -- Duncan Booth http://kupuguy.blogspot.com -- http://mail.python.org/mailman/listinfo/python-list
