Gnarlodious wrote:
On Jan 20, 10:35 pm, Steven D'Aprano wrote:
That's the wrong way to handle the problem. Named objects are only useful
if you know the name of the object when writing the code. Otherwise, how
do you know what name to use in the code?
Thank you for the help. I am gathering the names of all *.plist files
in a folder, creating objects named the filename, and accessing the
data like this:
Data.Server.Config.BaseURL
http://Spectrumology.com/
Adding a .plist file would automatically create a plist dictionary
object inside the Data module.
The right way to solve this problem is with a dictionary:
for name in ["object1", "object2", "object3"]:
d =name: classname()}
print d[name]
This works! However I end up saying:
d['Server'].Config.BaseURL
to get the data, when I should be saying:
Server.Config.BaseURL
but for the record, the way to use exec is like this:
exec("object1 =lassname()")
I failed to make that work. So back to the original question. How to
make an instance named according to a string inside a variable? I
guess it should be in the top-level namespace, not inside a list or
dictionary.
-- Gnarlie
http://Gnarlodious.com/Gnarlodious
I know you figure you have a specific list of files, and that they'll
never conflict with the other global variables you've defined. But
adding globals dynamically is "magic", and can lead to very obscure
bugs. Suppose sometime in the future somebody adds another plist file
with the same name as one of your functions?
Put it inside a dummy class, as follows:
>>> class Plist: pass
...
>>> plists = Plist()
>>> setattr(plists, "Server", 42)
>>> plists.Server
42
>>>
That avoids the ["Server"] syntax, but still doesn't risk polluting your
global namespace with arbitrary names. And in the example above, you'd
be using
plists.Server.Config.BaseURL
And if you must use the global namespace, you can simply do:
>>> globals()["Server"] = 42
>>> Server
42
DaveA
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