On Wed, Jan 13, 2010 at 5:46 AM, yamamoto <blueskykin...@gmail.com> wrote:
> Hi,
> I am new to Python. I'd like to extract "a" tag from a website by
> using "beautifulsoup" module.
> but it doesnt work!
>
> //sample.py
>
> from BeautifulSoup import BeautifulSoup as bs
> import urllib
> url="http://www.d-addicts.com/forum/torrents.php";
> doc=urllib.urlopen(url).read()
> soup=bs(doc)
> result=soup.findAll("a")
> for i in result:
> print i
>
>
> Traceback (most recent call last):
> File "C:\Users\falcon\workspace\p\pyqt\ex1.py", line 8, in <module>
> soup=bs(doc)
> File "C:\Python26\lib\site-packages\BeautifulSoup.py", line 1499, in
> __init__
> BeautifulStoneSoup.__init__(self, *args, **kwargs)
> File "C:\Python26\lib\site-packages\BeautifulSoup.py", line 1230, in
> __init__
> self._feed(isHTML=isHTML)
> File "C:\Python26\lib\site-packages\BeautifulSoup.py", line 1263, in
> _feed
> self.builder.feed(markup)
> File "C:\Python26\lib\HTMLParser.py", line 108, in feed
> self.goahead(0)
> File "C:\Python26\lib\HTMLParser.py", line 148, in goahead
> k = self.parse_starttag(i)
> File "C:\Python26\lib\HTMLParser.py", line 226, in parse_starttag
> endpos = self.check_for_whole_start_tag(i)
> File "C:\Python26\lib\HTMLParser.py", line 301, in
> check_for_whole_start_tag
> self.error("malformed start tag")
> File "C:\Python26\lib\HTMLParser.py", line 115, in error
> raise HTMLParseError(message, self.getpos())
> HTMLParser.HTMLParseError: malformed start tag, at line 276, column 36
>
> any suggestion?
> thanks in advance
>
> --
> http://mail.python.org/mailman/listinfo/python-list
>
BeautifulSoup is overkill for this anyways.
*#!/bin/python*from urllib import urlopen
html = urlopen("http://www.d-addicts.com/forum/torrents.php";).read()links
= set([link.split('"')[0] *for* link in html.split('href="')])
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