Mike Meyer wrote:
> > n = 0
> > for x in lst:
> > print "iteration %d on element %s" % (n, x)
> > n += 1
>
> Just for the record, the old idiom was:
>
> for n in xrange(len(lst)):
> x = lst[n]
> print "iteration %d on element %s" % (n, x)
it was? of the following four solutions,
for n in xrange(len(lst)):
x = lst[n]
...
for n in range(len(lst)):
x = lst[n]
...
n = 0
for x in lst:
...
n += 1
for x, n in enumerate(lst):
...
the xrange solution tends to be the slowest, especially for
relatively short lists (up to a 1000 elements, or so).
the exact details vary somewhat between Python versions,
but the += solution is always a good choice, and the xrange
solution is almost always a bad choice.
</F>
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