On Sun, 10 Jan 2010 22:21:54 -0800, Sebastian wrote: > Hi there, > > I have an array x=[1,2,3]
You have a list. Python has an array type, but you have to "import array" to use it. > Is there an operator which I can use to get the result > [1,1,1,2,2,2,3,3,3] ? Not an operator, but you can do it easily with a function. Here's the simple version: >>> def duplicate(items, count): ... L = [] ... for item in items: ... L.extend([item]*count) ... return L ... >>> duplicate([1,2,3], 3) [1, 1, 1, 2, 2, 2, 3, 3, 3] Here's a version which is short and simple enough to use in-line, but will be slow for large lists: >>> x = [1,2,3] >>> count = 3 >>> sum([[item]*count for item in x], []) [1, 1, 1, 2, 2, 2, 3, 3, 3] Finally, here's a nasty hack that you should never, ever, ever use for any reason except to win a bet: >>> [locals()['_[1]'].extend([item]*(count-1)) or item for item in x] [1, 1, 1, 2, 2, 2, 3, 3, 3] -- Steven -- http://mail.python.org/mailman/listinfo/python-list
