Somebody wrote: > If you actually need to perform comparisons across types, you can rely > upon the fact that tuple comparisons are non-strict and use e.g.: > > > a = 5 > > b = '5' > > (type(a).__name__, a) < (type(b).__name__, b) > True > > (type(a).__name__, a) > (type(b).__name__, b) > False > > The second elements will only be compared if the first elements are equal > (i.e. the values have the same type).
The same type *name*. To play it safe you'll have to compare the id, too: >>> items = [] >>> for i in range(2): ... class A: pass ... items.append(A()) ... >>> sorted(items, key=lambda a: (type(a).__name__, a)) Traceback (most recent call last): File "<stdin>", line 1, in <module> TypeError: unorderable types: A() < A() >>> sorted(items, key=lambda a: (type(a).__name__, id(type(a)), a)) [<__main__.A object at 0x14dfbd0>, <__main__.A object at 0x14dfc50>] Peter -- http://mail.python.org/mailman/listinfo/python-list
