On Jan 5, 8:58 pm, Phlip <phlip2...@gmail.com> wrote: > Hypo Nt: > > def each_with_index(seq): > index = 0 > result = [] > > for item in seq: > result.append([item, index]) > index += 1 > > return result > > My Pythonic sequencing skills are obviously feeble. Can anything think > of a way to write that in fewer lines? > > -- > Phlip > http://c2.com/cgi/wiki?MoreliaViridis
You could use the build-in function enumerate inside a list comprehension. >>> seq = range(5) >>> [ (i,s) for i,s in enumerate(seq) ] [(0, 0), (1, 1), (2, 2), (3, 3), (4, 4)] This will reduce the function to a one-liner. Regards, Marco -- http://mail.python.org/mailman/listinfo/python-list
