For posterity, I figured out a solution: > #!/usr/bin/python
> import sys > from traceback import extract_stack > varPassed="varName get" > def MyFunc(varPassed): > try: > raise None > except: > frame = sys._getframe(1) > print extract_stack(frame,2)[0][3] > MyFunc(varPassed) the print statement returns the full function call including parameters as they were written in the script (variable names and all) On Dec 28, 8:10 pm, Emile van Sebille <em...@fenx.com> wrote: > On 12/28/2009 3:54 PM Joel Davis said... > > > I'm just curious if anyone knows of a way to get the variable name of > > a reference passed to the function. > > For curiosity, sure -- but it's real weak... > > > Put another way, in the example: > > > def MyFunc ( varPassed ): > > print varPassed; > > > MyFunc(nwVar) > > > how would I get the string "nwVar" from inside of "MyFunc"? > > Here are some ways of doing > this:http://www.python-forum.org/pythonforum/viewtopic.php?f=14&t=12659 > > > is it possible? > > Yes -- but only for a limited set of situations. Consider the following: > > MyFunc(3) > > a=[1,2,3,4] > MyFunc(a[2]) > > b=a > MyFunc(b[2]) > > def newval(): return 3 > MyFunc(newval()) > > MyFunc(range(3)[-1]) > > Emile at first glance the solution i came up with seems to be in general the same as the one presented there, are there any portability issues you're aware of? also, when can one _not_ get the name? -- http://mail.python.org/mailman/listinfo/python-list
