"W. eWatson" <wolftra...@invalid.com> writes:
> Lie Ryan wrote:
> > what's strange about it? the difference between 2009/01/02 13:01:15
> > and 2009/01/04 13:01:15 is indeed 2 days... Can you elaborate what
> > do you mean by 'strange'?
> Easily. In one case, it produces a one argument funcion, and the other
> 2, possibly even a year if that differs.
In both cases it produces not a function, but a ‘datetime.timedelta’
object::
>>> import datetime
>>> t1 = datetime.datetime(2009, 1, 2, 13, 1, 15)
>>> t2 = datetime.datetime(2009, 1, 4, 13, 1, 15)
>>> type(t1)
<type 'datetime.datetime'>
>>> type(t2)
<type 'datetime.datetime'>
>>> dt = (t2 - t1)
>>> type(dt)
<type 'datetime.timedelta'>
What you're seeing in the interactive interpreter is a string
representation of the object::
>>> dt
datetime.timedelta(2)
This is no different from what's going on with any other string
representation. The representation is not the value.
> How does one "unload" this structure to get the seconds and days?
It's customary to consult the documentation for questions like that
<URL:http://docs.python.org/library/datetime.html#datetime.timedelta>.
> To find the difference more clearly. Why not just return (0,2,3555)
Because the ‘datetime.timedelta’ type is more flexible than a tuple, and
has named attributes as documented at the above URL::
>>> dt.days
2
>>> dt.seconds
0
>>> dt.microseconds
0
--
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Ben Finney
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