On Sun, 27 Dec 2009 19:07:12 -0500, python wrote: > Hans, > >> Unfortunately, Windows is not a respectable OS. Unlike Unix, it allows >> two processes to bind to the same port. The theory is that this somehow >> allows the two processes to share their workload. One thing the OP can >> portably do, is try to connect() to the port. If that succeeds, then a >> server program is already running at that port, so he should exit. > > Thank you for your tip - spot on!
Beware of the converse, though. If a process *cannot* connect to the port, then it should *not* assume that another server *isn't* running. If two potential servers both start at the same time, and each tries to connect, then both will fail, but you don't want both to start, either. -- http://mail.python.org/mailman/listinfo/python-list
