how about re.findall(r'\w+.=\W\D+(\d+)?',str) ?
this will work for any string within id !
~Ukanth
On Dec 21, 6:06 pm, Oltmans <rolf.oltm...@gmail.com> wrote:
> On Dec 21, 5:05 pm, Umakanth <cum...@gmail.com> wrote:
>
> > How about re.findall(r'\d+(?:\.\d+)?',str)
>
> > extracts only numbers from any string....
>
> Thank you. However, I only need the digits within the ID attribute of
> the DIV. Regex that you suggested fails on the following string
>
> ----
> lksjdfls <div id ='amazon_345343'> kdjff lsdfs </div> sdjfls <div id
> = "amazon_35343433">sdfsd</div><div id='amazon_8898'>welcome</div>
> hello, my age is 86 years old and I was born in 1945. Do you know that
> PI is roughly 3.1443534534534534534
> ----
>
> > ~uk
>
> > On Dec 21, 4:38 pm, Oltmans <rolf.oltm...@gmail.com> wrote:
>
> > > Hello,. everyone.
>
> > > I've a string that looks something like
> > > ----
> > > lksjdfls <div id ='amazon_345343'> kdjff lsdfs </div> sdjfls <div id
> > > = "amazon_35343433">sdfsd</div><div id='amazon_8898'>welcome</div>
> > > ----
>
> > > From above string I need the digits within the ID attribute. For
> > > example, required output from above string is
> > > - 35343433
> > > - 345343
> > > - 8898
>
> > > I've written this regex that's kind of working
> > > re.findall("\w+\s*\W+amazon_(\d+)",str)
>
> > > but I was just wondering that there might be a better RegEx to do that
> > > same thing. Can you kindly suggest a better/improved Regex. Thank you
> > > in advance.
>
>
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