Malte Dik wrote:
> Hi out there!
>
> I want to put some intelligence into a csv reading script and in order to
> do so I want to compare possible different dialects I collect with some
> random
>
> d = csv.Sniffer().sniff("1,2,3,4"),
>
> because the csv is kinda dirty.
>
> Now sniff() returns a class object and those aren't comparable in the "if
> dialect_1 == dialect_2: count something" sense.
>
> Has anyone around here already dealt with this kind of problem and maybe
> even a solution I could utilize? That would be great.
An implementation for the lazy
>>> import csv
>>> d = csv.Sniffer().sniff("1,2,3")
>>> def eq(a, b, attributes=[name for name in dir(d) if not
name.startswith("_")]):
... return all(getattr(a, n, None) == getattr(b, n, None) for n in
attributes)
...
>>> eq(d, csv.Sniffer().sniff("3,4,5"))
True
>>> eq(d, csv.Sniffer().sniff("'3','4','5'"))
False
>>> eq(d, csv.Sniffer().sniff("3;4;5"))
False
>>> eq(d, csv.Sniffer().sniff("3,4,' 5'"))
True
> If not - I guess I would just write a quick function comparing the
> attributes of those dialects ... - but just out of educational curiosity:
> Would it be the right way to implement an __eq__(...) function into the
> Dialect class or how would someone who would want to make it right do it?
I don't know if you can do it for classic classes; for newstyle classes
you'd have to reimplement comparison in the metaclass:
>>> class Dialect:
... class __metaclass__(type):
... def __eq__(self, other):
... return self._key() == other._key()
... def __ne__(self, other):
... return self._key() != other._key()
... def _key(self):
... return self.quotechar, self.delimiter #,...
...
>>> class A(Dialect):
... quotechar = "'"
... delimiter = ":"
...
>>> class B(Dialect):
... quotechar = "'"
... delimiter = ","
...
>>> A == B
False
>>> B.delimiter = ":"
>>> A == B
True
On a side note, I think it's a C++ism that dialects are classes rather than
class instances. That's a superfluous complication since in Python no work
will be moved from compile time to runtime anyway.
Peter
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