On 12/14/09 2:24 AM, knifenomad wrote:
On 12월14일, 오전10시19분, knifenomad<knifeno...@gmail.com>  wrote:
On 12월14일, 오전2시57분, mattia<ger...@gmail.com>  wrote:





Il Sun, 13 Dec 2009 16:37:20 +0000, mattia ha scritto:
How can I insert non-duplicate data in a list? I mean, is there a
particular option in the creation of a list that permit me not to use
something like:
def append_unique(l, val):
     if val not in l:
         l.append(val)
Thanks,
Mattia
Ok, so you all suggest to use a set. Now the second question, more
interesting. Why can't I insert a list into a set? I mean, I have a
function that returns a list. I call this function several times and
maybe the list returned is the same as another one already returned. I
usually put all this lists into another list. How can I assure that my
list contains only unique lists? Using set does'n work (i.e. the python
interpreter tells me: TypeError: unhashable type: 'list')...
this makes the set type hashable.

class Set(set):
     __hash__ = lambda self: id(self)

s = Set()
s.add(1)
s.add(2)
s.add(1)

print s
set([1, 2])

d = {}
d[s] = 'voila'

print d
{Set([1,2]):'voila'}

print d[s]
'voila'- 원본 텍스트 숨기기 -

- 원본 텍스트 보기 -

although it's not what you've asked about. it's intereting to make set
hashable using __hash__.
Thoughtless messing with __hash__ is seldom useful.

>>> s1 = Set([1])
>>> s2 = Set([1])
>>> s1 == s2
True
>>> d = {}
>>> d[s1] = 3
>>> d[s2] = 5
>>> d
{Set([1]): 3, Set([1]): 5}
>>>

Equality is kept for comparison, but what is it worth to hash
them by id?

On the original problem:

You could turn you lists into tuples. This would be clean
and correct.

ciao - chris

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