Victor Subervi wrote:
printTree(aTree[name], level + 1)
... print aTree([name], level + 1)
...
Traceback (most recent call last):
File "<stdin>", line 4, in ?
TypeError: 'dict' object is not callable
>>>
Be cautious, you are now executing the same code !
Again, read carefully the error message, you tried to call a dictionary
: aTree([name], level + 1)
the following code below works fine in a python 2.5 shell:
allTrees = [{'prodCat1': {}, 'prodCat2': {}}, {'presCat1': {},
'presCat2': {}}]
level = 0
tree=[]
def printTree(allTrees, level=0):
for aTree in allTrees:
for name in sorted(aTree.keys()):
print '\t' * level, name
tree.append("%s%s" % ("\t" * level, name))
printTree(aTree[name], level + 1)
In [9]: run ~/test.py
In [10]: printTree(allTrees)
prodCat1
prodCat2
presCat1
presCat2
In [11]: print tree
['prodCat1', 'prodCat2', 'presCat1', 'presCat2']
Though I'm not sure this is exactly want you want.
Anyway, there is a big probelm happening when using the following value :
allTrees = [{'prodCat1': {'test':'success'}, 'prodCat2': {}},
{'presCat1': {}, 'presCat2': {}}]
printTree take a list in the first place, but when recursively calling
printTree(aTree[name], level + 1), you pass a dictionary. Your code will
fail as soon as the dictionary is not empty.
JM
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