On Nov 30, 5:24 pm, MRAB <pyt...@mrabarnett.plus.com> wrote:
> Jeremy wrote:
> > I am using re.split to... well, split a string into sections. I want
> > to split when, following a new line, there are 4 or fewer spaces. The
> > pattern I use is:
>
> > sections = re.split('\n\s{,4}[^\s]', lineoftext)
>
> > This splits appropriately but I lose the character matched by [^s]. I
> > know I can put parentheses around [^s] and keep the matched character,
> > but the character is placed in it's own element of the list instead of
> > with the rest of the lineoftext.
>
> > Does anyone know how I can accomplish this without losing the matched
> > character?
>
> First of all, \s matches any character that's _whitespace_, such as
> space, "\t", "\n", "\r", "\f". There's also \S, which matches any
> character that's not whitespace.
Thanks for the reminder. I knew \S existed, but must have forgotten
about it.
>
> But in answer to your question, use a look-ahead:
>
> sections = re.split('\n {,4}(?=\S)', lineoftext)
Yep, that does the trick. Thanks for the help!
Jeremy
--
http://mail.python.org/mailman/listinfo/python-list
