"mk" <mrk...@gmail.com> wrote in message news:he60ha$iv...@ger.gmane.org...
Hello,
>>> r=re.compile(r'(?:[a-zA-Z]:)([\\/]\w+)+')
>>> r.search(r'c:/tmp/spam/eggs').groups()
('/eggs',)
Obviously, I would like to capture all groups:
('/tmp', '/spam', '/eggs')
But it seems that re captures only the last group. Is there any way to
capture all groups with repeat following it, i.e. (...)+ or (...)* ?
Even better would be:
('tmp', 'spam', 'eggs')
Yes, I know about re.split:
>>> re.split( r'(?:\w:)?[/\\]', r'c:/tmp/spam\\eggs/' )
['', 'tmp', 'spam', '', 'eggs', '']
My interest is more general in this case: how to capture many groups with
a repeat?
re.findall is what you're looking for. Here's all words not followed by a
colon:
import re
re.findall(u'(\w+)(?!:)',r'c:\tmp\spam/eggs')
['tmp', 'spam', 'eggs']
-Mark
--
http://mail.python.org/mailman/listinfo/python-list