"Jon P." <jbpe...@gmail.com> writes:
> I'd like to do:
>
> resultlist = operandlist1 + operandlist2
That's an unfortunate way of expressing it; it's valid Python syntax
that doesn't do what you're describing (in this case, it will bind
‘resultlist’ to a new list that is the *concatenation* of the two
original lists).
> map(lambda op1,op2: op1 + op2, operandlist1, operandlist2)
>
> Is there any reasonable way to do this via a list comprehension ?
Yes, just about any ‘map()’ operation has a corresponding list
comprehension. (Does anyone know of a counter-example, a ‘map()’
operation that doesn't have a correspondingly simple list
comprehension?)
For the above case, this is how it's done::
>>> operandlist1 = [1, 2, 3, 4, 5]
>>> operandlist2 = [5, 4, 3, 2, 1]
>>> resultlist = [(a + b) for (a, b) in zip(operandlist1, operandlist2)]
>>> resultlist
[6, 6, 6, 6, 6]
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Ben Finney
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