Ben Finney wrote:
Robert Kern <robert.k...@gmail.com> writes:
If you are going to expose symbols in your __init__.py, they should
not have the same name as any of the modules in the package.
Would I be correct in assuming you make an exception for the package
importing one of the modules in the package, and thereby making that
module's identifier exposed?
package_foo/
__init__.py
module_bar.py
$ cat foo/__init__.py
import module_bar
Now the name ‘package_foo.module_bar’ will get the identifier already
assigned within ‘package_foo/__init__.py’, but that identifier is the
module anyway.
Yes.
--
Robert Kern
"I have come to believe that the whole world is an enigma, a harmless enigma
that is made terrible by our own mad attempt to interpret it as though it had
an underlying truth."
-- Umberto Eco
--
http://mail.python.org/mailman/listinfo/python-list
