On 2009-10-30 18:40 PM, Stef Mientki wrote:
Robert Kern wrote:
On 2009-10-30 12:19 PM, kj wrote:
How can a module determine the path of the file that defines it?
(Note that this is, in the general case, different from sys.argv[0].)
__file__
but for modules launched with execfile, __file__ doesn't exists.
Modules launched from execfile() using a properly initialized namespace dict do.
--
Robert Kern
"I have come to believe that the whole world is an enigma, a harmless enigma
that is made terrible by our own mad attempt to interpret it as though it had
an underlying truth."
-- Umberto Eco
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