On Oct 26, 7:28 am, Vlastimil Brom <vlastimil.b...@gmail.com> wrote:
> 2009/10/26 jhermann <juergen.herm...@1und1.de>:
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> > On 16 Okt., 02:18, Mensanator <mensana...@aol.com> wrote:
> >> All I wanted to do is split a binary number into two lists,
> >> a list of blocks of consecutive ones and another list of
> >> blocks of consecutive zeroes.
>
> > Back to the OP's problem, the obvious (if you know the std lib) and
> > easy solution is:
>
> >>>> c = '001010111100101'
> >>>> filter(None, re.split("(1+)", c))
> > ['00', '1', '0', '1', '0', '1111', '00', '1', '0', '1']
>
> > In production code, you compile the regex once, of course.
> > --
> >http://mail.python.org/mailman/listinfo/python-list
>
> Maybe one can even forget the split function here entirely
>
> >>> re.findall(r"0+|1+", '001010111100101')
>
> ['00', '1', '0', '1', '0', '1111', '00', '1', '0', '1']
>Very good. Thanks to both of you. Now if I could only remember why I wanted to do this. > > > vbr -- http://mail.python.org/mailman/listinfo/python-list
