Mensanator <mensana...@aol.com> writes: > Thanks, but what I wanted was > ['00','1','0','1','0','1111','00','1','0' '1'].
>>> c = '001010111100101'
>>> list(''.join(g) for k,g in groupby(c))
['00', '1', '0', '1', '0', '1111', '00', '1', '0', '1']
is really not that unnatural.
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