Shaun wrote:
> testDict = {}
> ...
> testDict [1] = testDict.get (1, []).append ("Test0") # 1 does not
> exist, create empty array
> print testDict
> testDict [1] = testDict.get (1, []).append ("Test1")
> print testDict
>
[ ... ]
> However, the first printout gives {1: None} instead of the desired
> {1: ['test']}. What's wrong with this syntax?
The trouble is that the list.append method returns None, after modifying the
value of the parent list in place. So of course, None gets assigned to
testDict[1] after the valuable work has been done.
The old way to do what you want is
testDict.setdefault (1, []).append ("Test0")
The new way is to inherit from defaultdict.
Mel.
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