In <mailman.429.1253825725.2807.python-l...@python.org> Robert Kern <robert.k...@gmail.com> writes:
>On 2009-09-24 14:40 PM, kj wrote: >> >> The docs for divmod include the following: >> >> divmod(a, b) >> ...For floating point numbers the result is (q, a % b), where q >> is usually math.floor(a / b) but may be 1 less than that. ... >> >> I know that floating point math can sometimes produce "unexpected" >> results, so the above caveat is not entirely surprising. Still, >> I would find it helpful to see a specific example where >> divmod(a, b)[0] is equal to math.floor(a/b)-1. Does anybody know >> one? >In [21]: a = 10.0 >In [22]: b = 10.0 / 3.0 >In [24]: divmod(a, b)[0] >Out[24]: 2.0 >In [25]: math.floor(a / b) - 1.0 >Out[25]: 2.0 Wow. To me this stuff is just black magic, with a bit of voodoo added for good measure... Maybe some day I'll understand it. Thanks! kynn -- http://mail.python.org/mailman/listinfo/python-list
