Building on the answers of the others, a simple one liner, no side effect, not the fastest I guess:
>>> d={'a': 'bob', 'b': 'stu'}
>>> set( d.keys() ).difference( [ 'a' ] ).pop()
'b'
Note the square brackets for the parameter of difference(). 'The
string 'a' and the list [ 'a' ] are both iterable but really are
different.
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