On Sep 9, 3:27 am, sturlamolden <sturlamol...@yahoo.no> wrote: > On 9 Sep, 00:24, Steven D'Aprano > > <ste...@remove.this.cybersource.com.au> wrote: > > A decent vendor-supplied implementation will include error checking that > > you otherwise would need to implement yourself, so yes. > > Not for code like this: > > > > >>> import numpy as np > >>> n = np.arange(101) > >>> w = 0.5*(1.0-np.cos(2*np.pi*n/(100.)))
Well, I went and dug into NumPy. They write it as 0.5 - 0.5 * cos (...), and special case N = 1, and properly error check N < 1. Still, probably because of differences in dictionary look ups (because of namespace scopes), np.hanning, on average, takes a wee bit over half as long as your case, and yours is only a shade faster than >>> window = [0.5 - math.cos(2 * x * math.pi /100.) for x in range(101)] (Yes, I know I should've used xrange instead of range) -- http://mail.python.org/mailman/listinfo/python-list
