"Martin" <mdeka...@gmail.com> wrote in message
news:5941d8f1-27c0-47d9-8221-d21f07200...@j39g2000yqh.googlegroups.com...
Hi,
I need to extract a string after a matching a regular expression. For
example I have the string...
s = "FTPHOST: e4ftl01u.ecs.nasa.gov"
and once I match "FTPHOST" I would like to extract
"e4ftl01u.ecs.nasa.gov". I am not sure as to the best approach to the
problem, I had been trying to match the string using something like
this:
m = re.findall(r"FTPHOST", s)
But I couldn't then work out how to return the "e4ftl01u.ecs.nasa.gov"
part. Perhaps I need to find the string and then split it? I had some
help with a similar problem, but now I don't seem to be able to
transfer that to this problem!
In regular expressions, you match the entire string you are interested in,
and parenthesize the parts that you want to parse out of that string. The
group() method is used to get the whole string with group(0), and each of
the parenthesized parts with group(n). An example:
s = "FTPHOST: e4ftl01u.ecs.nasa.gov"
import re
re.search(r'FTPHOST: (.*)',s).group(0)
'FTPHOST: e4ftl01u.ecs.nasa.gov'
re.search(r'FTPHOST: (.*)',s).group(1)
'e4ftl01u.ecs.nasa.gov'
-Mark
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