Hi all
I have a class that uses a dictionary to map message numbers to methods.
Here is a simple example -
class MyClass(object):
def __init__(self):
self.method_dict = {}
self.method_dict[0] = self.method_0
self.method_dict[1] = self.method_1
def on_message_received(self, msg):
self.method_dict[msg]()
def method_0(self):
print 'in method_0'
def method_1(self):
print 'in method_1'
I have quite a few methods, so the dictionary is growing - up to 28 methods
so far. To avoid
having to recreate the dictionary every time I create an instance of the
class, I tried to move it
up to the class level. Unfortunately it does not work. This is what I
tried -
class MyClass(object):
method_dict = {}
method_dict[0] = method_0 # this gives an error
method_dict[1] = method_1
def on_message_received(self, msg):
self.method_dict[msg]()
def method_0(self):
print 'in method_0'
def method_1(self):
print 'in method_1'
As written above, I get the following error -
NameError: name 'method_0' is not defined
If I try self.method_0, I get 'self' is not defined.
If I try __class__.method_0, I get '__class__' is not defined.
If I try MyClass.method_0, I get 'MyClass' is not defined.
Is there any variation on this theme that will work?
#----------------------------------------------------
Ok, I found a variation that seems to work.
Is this the preferred way, or is there a better alternative?
class MyClass(object):
def on_message_received(self, msg):
#self.method_dict[msg]() # had to change this to get it to work
self.method_dict[msg](self)
def method_0(self):
print 'in method_0'
def method_1(self):
print 'in method_1'
MyClass.method_dict = {}
MyClass.method_dict[0] = MyClass.method_0
MyClass.method_dict[1] = MyClass.method_1
As you can see, I had to add 'self' to the method arguments when calling the
method.
Any comments?
Thanks
Frank Millman
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