ryles wrote:
On Aug 14, 8:22 pm, candide <cand...@free.invalid> wrote:
Suppose you need to split a string into substrings of a given size (except
possibly the last substring). I make the hypothesis the first slice is at the
end of the string.
A typical example is provided by formatting a decimal string with thousands
separator.
What is the pythonic way to do this ?
For my part, i reach to this rather complicated code:
# ----------------------
def comaSep(z,k=3, sep=','):
z=z[::-1]
x=[z[k*i:k*(i+1)][::-1] for i in range(1+(len(z)-1)/k)][::-1]
return sep.join(x)
# Test
for z in ["75096042068045", "509", "12024", "7", "2009"]:
print z+" --> ", comaSep(z)
# ----------------------
outputting :
75096042068045 --> 75,096,042,068,045
509 --> 509
12024 --> 12,024
7 --> 7
2009 --> 2,009
Thanks
py> s='1234567'
py> ','.join(_[::-1] for _ in re.findall('.{1,3}',s[::-1])[::-1])
'1,234,567'
py> # j/k ;)
If you're going to use re, then:
>>> for z in ["75096042068045", "509", "12024", "7", "2009"]:
print re.sub(r"(?<=.)(?=(?:...)+$)", ",", z)
75,096,042,068,045
509
12,024
7
2,009
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