On Aug 12, 7:49 am, andrew cooke <and...@acooke.org> wrote: > On Aug 12, 1:51 am, James Stroud <nospamjstroudmap...@mbi.ucla.edu> > wrote: > > > > > andrew cooke wrote: > > > Is there a way to make this work (currently scope and join are > > > undefined at runtime when the inner class attributes are defined): > > > > class _StreamFactory(object): > > > > @staticmethod > > > def __call__(lines, source, join=''.join): > > > > class Line(object): > > > > __source = source > > > __join = join > > > [...] > > > It would be helpful if you were to describe the type of behavior you expect. > > Sorry, I didn't make myself clear. When run the code gives > NameError: name 'source' is not defined > because the class namespace blocks the function namespace (or > something...).
ie when the __call__ method is invoked on an instance of _StreamFactory. > Andrew -- http://mail.python.org/mailman/listinfo/python-list
