alex23 schrieb:
On Aug 7, 10:50 pm, Benjamin Kaplan <benjamin.kap...@case.edu> wrote:
That isn't an operator at all. Python does not support compound
comparisons like that. You have to do "a > b and b > c".
You know, it costs nothing to open up a python interpreter and check
your certainty:
x = 10
1 < x < 20
True
This is a _very_ common pattern.
class X(object):
... def __lt__(self, other):
... print 'in lt'
... return True
... def __gt__(self, other):
... print 'in gt'
... return True
...
x = X()
1 < x < 20
in gt
in lt
True
20 < x < 1
in gt
in lt
True
dmitrey: Diez' advice was the best you received.
Not really. I didn't get the chaining, and Peter is right that for that
there is no real overloading.
Diez
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