In <mailman.4178.1249331189.8015.python-l...@python.org> Albert Hopkins
<mar...@letterboxes.org> writes:
>On Mon, 2009-08-03 at 19:59 +0000, kj wrote:
>>
>> I want to write a decorator that, among other things, returns a
>> function that has one additional keyword parameter, say foo=None.
>>
>> When I try
>>
>> def my_decorator(f):
>> # blah, blah
>> def wrapper(*p, foo=None, **kw):
>> x = f(*p, **kw)
>> if (foo):
>> # blah, blah
>> else
>> # blah blah
>> return wrapper
>>
>> ...i get a syntax error where it says "foo=None". I get similar
>> errors with everything else I've tried.
>>
>Not exactly sure what you're trying to do..
Yeah, I wasn't too clear. I figured out how to do what I wanted
to do:
def my_decorator(f):
# blah, blah
def wrapper(*p, **kw):
foo = kw.pop('force', None)
x = f(*p, **kw)
if (foo):
# blah, blah
else
# blah blah
return wrapper
Now the definitions of the original functions do not include the
foo=None argument, but "actual" functions (i.e. the ones generated
by the decorator) all accept the optional foo parameter. The only
remaining problem is how to document this... I don't see how pydoc
could possibly figure this one out. I guess this is sufficient
argument to abandon this idea. Bummer.
kynn
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