Hi, I would like to ask how I should set timeout for a call:
f = urllib2.urlopen(url) I am using Python 2.5. I have already tried socket.setdefaulttimeout(3). However, this adversely affects other connections the application makes, since it seems to affect all socket connections. I know that Python 2.6 offers urllib2.urlopen(url[, data][, timeout]) which would elegantly solved my problem, but I have to stick to Python 2.5. I am doing urlopen in a thread so I want to avoid really long hanging on this call, which happens at times, until some default timeout ticks out. All hints appreciated. Thanks, Zdenek -- http://mail.python.org/mailman/listinfo/python-list
