On Jul 23, 2:45 am, "F.O.P." <f.orndorffplunk...@gmail.com> wrote: > On Jul 22, 9:07 am, "Rhodri James" <rho...@wildebst.demon.co.uk> > wrote: > > > > > > > > > On Wed, 22 Jul 2009 15:46:09 +0100, F.O.P. <f.orndorffplunk...@gmail.com> > > wrote: > > > >http://bugs.python.org/issue5358 > > > I simply installed 3.0 on my ubuntubox brought my project from a > > > windows machine and made necessary changes to what I had used from os > > > and os.path. I have an error at the end of this line: > > > for k in range(I): > > > and the error: > > > SyntaxError: invalid character in identifier > > > > I've already declared I way above as the lenth of an array (I = len > > > (IA)) > > > There shouldn't be a problem there aren't any issues with other > > > declarations identical to this. > > > Could you show us slightly more of your code and the rest of the > > error message, please? I have a suspicion that the error actually > > lies in the "necessary changes" you made. > > > -- > > Rhodri James *-* Wildebeest Herder to the Masses > > I spoke to a friend about it and he found that I had put in a unicode > "semicolon" rather than ASCII.
This is rather puzzling. What are you describing as a "unicode semicolon"? Possibilities include: (a) U+003B SEMICOLON (which is exactly what you need) (b) U+037E GREEK QUESTION MARK (which looks like (a)) (c) U+061B ARABIC SEMICOLON (which looks like (a) rotated 180 degrees) How did you get it into your source file? What was in your # coding: ????? or similar line at the top of your source file? -- http://mail.python.org/mailman/listinfo/python-list
