En Sat, 18 Jul 2009 12:31:46 -0300, Alan G Isaac <alan.is...@gmail.com>
escribió:
On Fri, 17 Jul 2009 05:19:50 +0000, Alan G Isaac wrote:
def apply2(itr, methodname, *args, **kwargs):
f = operator.methodcaller(methodname, *args, **kwargs)
for item in itr:
f(item)
On 7/17/2009 3:45 AM Steven D'Aprano apparently wrote:
for obj in objects:
getattr(obj, methodname)(*args, **kwargs)
Are there any obvious considerations in choosing
between those two?
The operator.methodcaller version is faster in my tests for large
collections, but slightly slower when you have very few elements.
<code>
import operator
import timeit
class X:
def method(self, x, y, **kw): pass
def apply1(itr, methodname, *args, **kwargs):
for item in itr:
getattr(item, methodname)(*args, **kwargs)
def apply2(itr, methodname, *args, **kwargs):
f = operator.methodcaller(methodname, *args, **kwargs)
for item in itr:
f(item)
L=[X() for _ in range(3000)]
apply1(L,'method', 1, 2, foo=3)
apply2(L,'method', 1, 2, foo=3)
timeit.timeit(setup="from __main__ import apply1,apply2,L",
stmt="apply1(L,'method', 1, 2, foo=3)", number=1000)
timeit.timeit(setup="from __main__ import apply1,apply2,L",
stmt="apply2(L,'method', 1, 2, foo=3)", number=1000)
</code>
--
Gabriel Genellina
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