Sion Arrowsmith wrote:
Jack Diederich <jackd...@gmail.com> wrote:
It isn't an OrderedDict thing, it is a comparison thing. Two regular
dicts also raise an error if you try to LT them.
Since when?
Python 2.5.2 (r252:60911, Jan 4 2009, 17:40:26)
[GCC 4.3.2] on linux2
Type "help", "copyright", "credits" or "license" for more information.
d1 = dict((str(i), i) for i in range (10))
d2 = dict((str(i), i) for i in range (20))
d1 < d2
True
Try reversing the definitions of d1 and d2. The dicts are probably being
compared by id (address), which is the 2.x CPython default.
(Don't have a 2.6 or 3 to hand.)
2.6 same. 3.1
>>> d1,d2 = {},{}
>>> d1 < d2
Traceback (most recent call last):
File "<pyshell#16>", line 1, in <module>
d1 < d2
TypeError: unorderable types: dict() < dict()
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