I did initially ask for an infix xor operator, but eventually gave up on this. I like the first of your two one-line solutions below; this is clean and easy to understand. Thanks! I'd still like to be able to write an expression like '(a and b) xor (c and d) xor (e and f)', but it looks as though that can't be done.
<snip> Well, that's not exactly what you originally asked for. But it's still a one-liner: def xor(*args): return bool(sum(map(bool, args)) % 2) or perhaps def xor(*args): return bool(len(filter(None, args)) & 1) -- View this message in context: http://www.nabble.com/missing-%27xor%27-Boolean-operator-tp24485116p24503248.html Sent from the Python - python-list mailing list archive at Nabble.com. -- http://mail.python.org/mailman/listinfo/python-list
