Irmen de Jong wrote:
[EMAIL PROTECTED] wrote:
How can we make only one thread at a time be able to access and
increment i ?
Use a synchronization primitive such as a lock
(threading.Lock, threading.RLock)
But for simply incrementing a number (i+=1) this is not needed
because that operation cannot be interrupted by another thread,
as far as I know.
Most assuredly it can:
>>> def f():
... global x
... x += 1
...
>>> dis.dis(f)
3 0 LOAD_GLOBAL 0 (x)
3 LOAD_CONST 1 (1)
6 INPLACE_ADD
...a context-change here can lead to incorrect results...
7 STORE_GLOBAL 0 (x)
10 LOAD_CONST 0 (None)
13 RETURN_VALUE
-Peter
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