[EMAIL PROTECTED] wrote: ...
list = [[10,11,12,13,14,78,79,80,81,300,301,308]]
how do I convert it so that I arrange them into bins .
so If i hvae a set of consecutive numbers i would like to represent
them as a range in the list with max and min val of the range alone.
I shd get something like list = [[10,14],[78,81],[300,308]]
Mage:
Maybe:
list = [10,11,12,13,14,78,79,80,81,300,301,308]
new_list = [] start = 0 for i in range(1,len(list) + 1): if i == len(list) or list[i] - list[i-1] <> 1: new_list.append([list[start],list[i-1]]) start = i
print new_list
[EMAIL PROTECTED] wrote:
yes that makes sense.But the problem I am facing is if list= [300,301,303,305] I want to consider it as one cluster and include the range as [300,305] so this is where I am missing the ranges. so If the list has l = [300,301,302,308,401,402,403,408] i want to include it as [[300,308],[401,408]].
Mage's solution meets the requirements that you initially stated of treating *consecutive* numbers as a group. Now you also want to consider [300,301,303,305] as a cluster.
You need to specify your desired clustering rule, or alternatively specify ho many bins you want to create, but as an example, here is a naive approach, that could be adapted easily to other clustering rules and (a bit less easily) to target a certain number of bins
def lstcluster(lst):
# Separate neighbors that differ by more than the mean difference
lst.sort()
diffs = [(b-a, (a, b)) for a, b in zip(lst,lst[1:])]
mean_diff = sum(diff[0] for diff in diffs)/len(diffs)
breaks = [breaks for diff, breaks in diffs if diff > mean_diff]
groups = [lst[0]] + [i for x in breaks for i in x] + [lst[-1]]
igroups = iter(groups) # Pairing mechanism due to James Stroud
return [[i, igroups.next()] for i in igroups]Note this is quite inefficient due to creating several intermediate lists. But it's not worth optimizing yet, since I'm only guessing at your actual requirement.
lst0 = [10,11,12,13,14,78,79,80,81,300,301,308] lst1 = [10,12,16,24,26,27,54,55,80,100, 105] lst3 = [1,5,100,1000,1005,1009,10000, 10010,10019]
>>> lst0 = [10,11,12,13,14,78,79,80,81,300,301,308] >>> lst1 = [10,12,16,24,26,27,54,55,80,100, 105] >>> lst2 = [1,5,100,1000,1005,1009,10000, 10010,10019] >>> lstcluster(lst0) [[10, 14], [78, 81], [300, 308]] >>> lstcluster(lst1) [[10, 27], [54, 55], [80, 80], [100, 105]] >>> lstcluster(lst2) [[1, 1009], [10000, 10019]] >>>
Michael
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