Steven D'Aprano <st...@remove-this-cybersource.com.au> writes: > groupby() works on lists.
>>> a = [1,3,4,6,7] >>> from itertools import groupby >>> b = groupby(a, lambda x: x%2==1) # split into even and odd >>> c = list(b) >>> print len(c) 3 >>> d = list(c[1][1]) # should be [4,6] >>> print d # oops. [] > The difference between what I'm suggesting and what groupby() does is > that my suggestion would collate *all* the elements with the same key, > not just runs of them. This (as far as I can tell) requires returning > lists rather than iterators. I guess that is reasonable. > The most important difference between my suggestion and that of the OP is > that he limited the key function to something which returns a truth > value, while I'm looking for something more general which can split the > input into an arbitrary number of collated sublists. Also ok. -- http://mail.python.org/mailman/listinfo/python-list
