sato.ph...@gmail.com a écrit :
Thank you for all of the help. With your assistance and help from the
Python Tutor mailing list I was able to come up with the following
code:
password = "qwerty"
correct_password_given = False
guess = "0"
You could just use None here:
guess=None
count = 0
while count != 3 and not correct_password_given :
guess = raw_input("Enter your password: ")
guess = str(guess)
IIRC, raw_input() already returns a string !-)
if guess != password:
print "Access Denied"
count = count + 1
Or:
count += 1
else:
print "Password Confirmed"
correct_password_given = True
If I understand it correctly, the function will continue to loop until
either the count == 3 or until correct_password_give = True,
There are many ways to write a same boolean test, and some are easier to
understand. Your test could be written:
while not (count == 3 or correct_password_given) :
# proceed
Does it answer your question ?-)
As a general rule:
* not A and not B <=> not (A or B)
* not A or not B <=> not (A and B)
satisfying the two conditions of the assignment, which were to lock a
user out after three failed password attempts and to print "Access
Granted" and end the module if the correct password is given.
Well, given your snippet, execution indeed terminates after either
successful 'login' or 3 failed attempts, but that's mostly because
there's no code to execute after the while loop...
--
http://mail.python.org/mailman/listinfo/python-list
