On Mon, Jun 29, 2009 at 2:17 PM, Christian Heimes<li...@cheimes.de> wrote: > "if file in os.list()" is slow and not correct. You have to check if the > file is either a real file or a symlink to a file and not a directory or > special. Then you have to verify that the file has the executable bit, too.
I realize four lines of Python does not replicate the functionality of which exactly. It was intended to give the original poster something to start with. I am curious about it being slow, though. Is there a faster way to get the contents of a directory than os.listdir() or is there a faster way to see if an element is in a list other than "x in y"? I believe 'which' will terminate once it finds any match, which mine does not, but that can be fixed by adding a break after the print. -- http://mail.python.org/mailman/listinfo/python-list
