"aberry" <abe...@aol.in> wrote in message
news:24164207.p...@talk.nabble.com...
Mark Tolonen-3 wrote:
"aberry" <abe...@aol.in> wrote in message
news:24146775.p...@talk.nabble.com...
I am facing an error on Unicode decoding of path if it contain a
folder/file
name starting with character 'u' .
Here is what I did in IDLE
1. >>> fp = "C:\\ab\\anil"
2. >>> unicode(fp, "unicode_escape")
3. u'C:\x07b\x07nil'
4. >>> fp = "C:\\ab\\unil"
5. >>> unicode(fp, "unicode_escape")
6.
7. Traceback (most recent call last):
8. File "<pyshell#41>", line 1, in <module>
9. unicode(fp, "unicode_escape")
10. UnicodeDecodeError: 'unicodeescape' codec can't decode bytes in
position
5-9: end of string in escape sequence
11. >>>
Not sure whether I am doing something wrong or this is as designed
behavior
.
any help appreciated
What is your intent? Below gives a unicode strings with backslashes. No
need for unicode_escape here.
fp = "C:\\ab\\unil"
fp
'C:\\ab\\unil'
print fp
C:\ab\unil
unicode(fp)
u'C:\\ab\\unil'
print unicode(fp)
C:\ab\unil
u'C:\\ab\\unil'
u'C:\\ab\\unil'
print u'C:\\ab\\unil'
C:\ab\unil
thanks all for help...
actually this was in old code having 'unicode_escape' .
i hope it was there to handle path which may contain localized chars...
but removing unicode_escape' it worked fine... :)
If that was the case, then here's a few other options:
print 'c:\\\\abc\\\\unil\\xe4'.decode('unicode_escape')
c:\abc\unilä
print r'c:\\abc\\unil\xe4'.decode('unicode_escape')
c:\abc\unilä
print u'c:\\abc\u005cunil\u00e4'
c:\abc\unilä
print ur'c:\abc\u005cunil\u00e4'
c:\abc\unilä
You can also use forward slashes as another poster mentioned. If you want
to display the filenames with the backslashes, os.path.normpath can be used:
print os.path.normpath('c:/abc/unil\u00e4'.decode('unicode_escape'))
c:\abc\unilä
Note you only have to jump through these hoops to generate hard-coded
filenames with special characters. If they are already on disk, just read
them in with something like os.listdir(u'.'), which generates a list of
unicode filenames.
-Mark
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