On Jun 17, 1:26 pm, Jaime Fernandez del Rio <jaime.f...@gmail.com> wrote: > P.S. The snowflake curve, on the other hand, is uniformly continuous, right?
The definition of uniform continuity is that, for any epsilon > 0, there is a delta > 0 such that, for any x and y, if x-y < delta, f(x)-f (y) < epsilon. Given that Koch's curve is shaped as recursion over the transformation from ___ to _/\_, it's immediately obvious that, for a delta of at most the length of ____, epsilon will be at most the height of /. It follows that, inversely, for any arbitrary epsilon, you find the smallest / that's still taller than epsilon, and delta is bound by the respective ____. (hooray for ascii demonstrations) Curiously enough, it's the recursive/self-similar nature of the Koch curve so easy to prove as uniformly continuous. -- http://mail.python.org/mailman/listinfo/python-list
