Lawrence D'Oliveiro <l...@geek-central.gen.new_zealand> writes: > I don't think any countable set, even a countably-infinite set, can have a > fractal dimension. It's got to be uncountably infinite, and therefore > uncomputable.
I think the idea is you assume uniform continuity of the set (as expressed by a parametrized curve). That should let you approximate the fractal dimension. As for countability, remember that the reals are a separable metric space, so the value of a continuous function any dense subset of the reals (e.g. on the rationals, which are countable) completely determines the function, iirc. -- http://mail.python.org/mailman/listinfo/python-list
